Arithmetic Ability
 Probability

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Q.

In a single throw of two dice , find the probability that neither a doublet nor a total of 8 will appear.

View Answer

Correct choice: B

Explanation:

n(S) = 36 A = {(1, 1), (2, 2), (3, 3), (4, 4), (5, 5), (6, 6)} B = { (2, 6), (3, 5), (4, 4), (5, 3), (6, 2) } n(A)=6, n(B)=5, n(A∩B)=1 ∴ Required probability = P(A∪B) = P(A)+P(B)−P(A∩B) = 6/36+5/36−1/36 = 5/18
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